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So,y(t) = 2.5e^-t cos2t I

  1. 1) show that: 1-cos2t divided by sin2t= TANt2) show that: 1-(cos2t divided by (cos x cos)t)= (TAN x TAN)t
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    2. Craig asked by Craig
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  2. How to solve 2.5e^-t cos2t=0?
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    2. Gordon asked by Gordon
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  3. Find dy/dx if y=cos2t, x=sint
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    2. Sinachi asked by Sinachi
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  4. 1) (sin2t) (cos5t) + (cos2t) (sin5t)2) {1/(sec x - 1)} - {1/(sec x +1)} = 2 cot^2 x
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    2. Britt asked by Britt
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  5. If f is a vector-valued function defined by <sin2t, cos2t> then what is f '' (pi/4)?I think it is <-4, -√2/2>.
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    2. Anonymous asked by Anonymous
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  6. Use identities to simplify each expression.1) (sin2t) (cos5t) + (cos2t) (sin5t) 2) {1/(sec x - 1)} - {1/(sec x +1)} = 2 cot^2 x
    1. answers icon 1 answer
    2. Britt asked by Britt
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  7. find the tangent line equation at x=cost+sin2t, y=sint+cos2t, t=0
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    2. Lielle asked by Lielle
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  8. Find the equation of the line tangent to the parametric curve define byx=cos2t and y=sin3t and t=pi/12 plz i don't no where to
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    2. Collins asked by Collins
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  9. So,y(t) = 2.5e^-t cos2tI need to find the derivative, which is y'(t)= -2.5e^-t(2sin 2t +cost 2t) . And now I need to find t when
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    2. Gordon asked by Gordon
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  10. the path of a particle in the xy-plane is vector r = (cos2t, sint) for t for all [-pi/2, pi] where t represents time. Sketch the
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    2. mark asked by mark
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