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Sin2x/1-Cos2x
Solve identity,
(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
3 answers
asked by
sh
748 views
Solve the equation of the interval (0, 2pi)
cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
4 answers
asked by
Brian
797 views
solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie)
3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x =
3 answers
asked by
Julie
1,075 views
sinx = 4/5 and x terminates in Quadrant II
Find sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?
1 answer
asked by
Amandeep
1,757 views
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2x
ive tried this problem so many times I need help with
1 answer
asked by
Maria
1,531 views
prove sin2x+cos2x+1 tan(pi/4+x)
______________ = __________ sin2x+cos2x-1 tanx so what I did tan(x)
2 answers
asked by
Lana
751 views
prove that
1+sin2x-cos2x / sin2x+cos2x = tanx
1 answer
asked by
Anonymous
1,364 views
Prove that sin2x+cos2x-1/sin2x+cos2x+1=tanx
1 answer
asked by
James
1,246 views
cotx = -2 and 0 less than or equal to x less than or equal to pi
Find sin2x and cos2x How to get the answers of sin2x = -4/5,
1 answer
asked by
Amandeep
667 views
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
0 answers
asked by
Kalen
567 views