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Simplify :1/1-cosx +1/1+cos x
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
asked by
Anonymous
1,105 views
Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1 answer
asked by
Anonymous
1,385 views
Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
4 answers
asked by
Anonymous
1,977 views
Use the fundamental identities to simplify the expression.
csc Q / sec Q so this would be 1/sinx / 1/cosx and then 1/sinx times
1 answer
asked by
Hannah
589 views
Use the fundamental identities to simplify the expression.
csc Q / sec Q so this would be 1/sinx / 1/cosx and then 1/sinx times
1 answer
asked by
Hannah
613 views
Use the fundamental identities to simplify the expression.
csc Q / sec Q so this would be 1/sinx / 1/cosx and then 1/sinx times
1 answer
asked by
Hannah
645 views
How do you simplify:
(1/(sin^2x-cos^2x))-(2/cosx-sinx)? I tried factoring and creating a LCD of (sinx+cosx)(sinx cosx)
2 answers
asked by
Shannon
608 views
Simplify: (1/secx+sin^2x/cosx)cosx.
Explain alittle bit, not just do the steps please.
1 answer
asked by
does it matter at this point?
475 views
hey, i would really appreciate some help solving for x when:
sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
0 answers
asked by
elle
751 views
I have a question relating to limits that I solved
lim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by
1 answer
asked by
Alex
712 views