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Show that sin70°+sin50°= √3cos0°
Show that sin70°+sin50°= √3cos0°
1 answer
64 views
Prove that
sin50° - sin70° + sin10° = 0
0 answers
asked by
Kewal
505 views
(Cos70-cos50)÷(sin70-sin50) =-√3
1 answer
73 views
the triangle CDE, m<D=90 degrees, m<C=50 degrees, and ED=23. Which equation could be used to find CE?
1. sin50=CE/23 2.
1 answer
asked by
B8
559 views
Solve each equation for 0 <_ 0<_ 2Pi(3.14)
i) 18sin^20 +3cos0 - 17 = 0
1 answer
asked by
Lily Chang
372 views
Solve each equation for 0<_ 0<_ 2pi(3.14)
E) 18sin^2(0) + 3cos0 -17 =0
1 answer
asked by
Miu Lily
393 views
[Cos70°- cos60°]÷[sin 70°- sin50°]= -√3
1 answer
74 views
(Cos 70+cos20)÷ (sin70+sin20)
1 answer
57 views
cos45cos25 - sin 45sin25 = ??
a. cos70 b. sin70 c. cos 20 d. sin 20 which answer is correct ?
1 answer
asked by
Don
614 views
If 𝑎 = sin70°,𝑏 = cos70°,𝑐 = tan70°,𝑑 = 1 , order them from the largest to the smallest.
3 answers
asked by
Anonymous
123 views