Show that sin70°+sin50°= √3cos0°

  1. Show that sin70°+sin50°= √3cos0°
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  2. Prove thatsin50° - sin70° + sin10° = 0
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    2. Kewal asked by Kewal
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  3. (Cos70-cos50)÷(sin70-sin50) =-√3
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  4. the triangle CDE, m<D=90 degrees, m<C=50 degrees, and ED=23. Which equation could be used to find CE?1. sin50=CE/23 2.
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    2. B8 asked by B8
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  5. Solve each equation for 0 <_ 0<_ 2Pi(3.14)i) 18sin^20 +3cos0 - 17 = 0
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    2. Lily Chang asked by Lily Chang
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  6. Solve each equation for 0<_ 0<_ 2pi(3.14)E) 18sin^2(0) + 3cos0 -17 =0
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    2. Miu Lily asked by Miu Lily
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  7. [Cos70°- cos60°]÷[sin 70°- sin50°]= -√3
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  8. (Cos 70+cos20)÷ (sin70+sin20)
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  9. cos45cos25 - sin 45sin25 = ??a. cos70 b. sin70 c. cos 20 d. sin 20 which answer is correct ?
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    2. Don asked by Don
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  10. If 𝑎 = sin70°,𝑏 = cos70°,𝑐 = tan70°,𝑑 = 1 , order them from the largest to the smallest.
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    2. Anonymous asked by Anonymous
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