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Show that 1-cos2A/Cos^2*A = tan^2*A
Show that 1-cos2A/Cos^2*A = tan^2*A
1-cos2A/Cos^2*A = [Cos^2(A) - Cos(2A)]/Cos^2(A). Substitute: Cos(2A) = 2Cos^2(A) - 1: [1 -
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Paul C
738 views
show that:
2^5 cos^2a sin^4a = cos6a-2cos4a- cos2a + 2
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Anonymous
372 views
show that:
2^5 cos^2a sin^4a=cos6a-2cos4a- cos2a + 2
2 answers
asked by
Anonymous
1,427 views
For the function f(x)=sinx, show with the formula sin^2A=1/2(1-cos2A) that f(x+y)-f(x)=cosxsiny-2sinxsin^2(1/2y)
4 answers
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Anonymous
1,835 views
By using the identity cos2A=1-2sin^2A show that cos4x = 1-8sin^2xcos^2x
2 answers
asked by
Shauna
689 views
Let A=(cosA -sinA)
(sinA cosA) show that A^2=(cos2A sin2A) (sin2A cos2A)
1 answer
asked by
James
642 views
how do you solve this.prove: cos2A plus cosA divided by sin2A minus sinA equal to cos2A plus 1 divided by sinA
1 answer
asked by
lungisile ntobela
1,156 views
Prove:
1/cos2A+sin2A/cos2A=sinA+cosA/cosA-sinA
1 answer
asked by
Piwo
1,201 views
Prove:
1/cos2A+sin2A/cos2A=sinA+cosA/cosA-sinA
1 answer
asked by
Piwo
610 views
cos²a + cos²(a+120°) + cos(a-120°) = 3/2
1 answer
asked by
Kewal
1,479 views