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Setting StartFraction 7 over 3
Setting StartFraction 7 over 3 EndFraction equal to which ratio would result in a valid proportion?
StartFraction 9 over 49
1 answer
72 views
Urvi solved a fraction division problem using the rule “multiply by the reciprocal.” Her work is shown below.
StartFraction
1 answer
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Simplify the complex fraction StartFraction StartFraction 1 over x EndFraction over StartFraction 2 over y EndFraction
1 answer
122 views
Which shows the correct way to use the rule “multiply by the reciprocal” for the expression below?
7 divided by StartFraction
1 answer
77 views
Which shows the correct way to use the rule “multiply by the reciprocal” for the expression below?
5 divided by StartFraction
1 answer
74 views
Which shows the correct way to use the rule “multiply by the reciprocal” for the expression below?
5 divided by StartFraction
1 answer
53 views
Use the work shown to find the solutions of the quadratic equation.
x2 – x – StartFraction 3 Over 4 EndFraction = 0 x2 – x
1 answer
asked by
Keontay
1,368 views
Use the work shown to find the solutions of the quadratic equation.
x2 – x – StartFraction 3 Over 4 EndFraction = 0 x2 – x
1 answer
asked by
Jerica
202 views
Which multiplication expression can be used to check this division problem: StartFraction 2 Over 5 EndFraction divided by
1 answer
61 views
After completing the fraction division StartFraction 7 Over 3 EndFraction divided by StartFraction 2 Over 9 EndFraction, Bai
1 answer
asked by
sssniperwolf
73 views