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Section Area: Use Riemann sums
Section Area:
Use Riemann sums and a limit to compute the exact area under the curve. y = 4x^2 - x on (a) [-0,1]; (b) [-1, 1];
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asked by
Sandra Gibson
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Use Riemann sums and limits to compute the area bounded by
f(x) = 10x+9 and the x axis between x=10 to x =5 The area is = to
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asked by
Anonymous
504 views
Well, first graph the graph of f(x)=-1/10x^2 + 3
2. We are going to approximate the area between f and the x-axis from x = 0 to x
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asked by
Yoona
814 views
Use the Left and Right Riemann Sums with 100 rectangles to estimate the (signed) area under the curve of y=−6x+8 on the
1 answer
asked by
Tyler
571 views
Use the Left and Right Riemann Sums with 80 rectangles to estimate the (signed) area under the curve of y=e2x−15 on the
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asked by
Will
295 views
Use the Left and Right Riemann Sums with 80 rectangles to estimate the (signed) area under the curve of y=e^2x−15 on the
1 answer
asked by
Will
470 views
Use the Left and Right Riemann Sums with 80 rectangle to estimate the (signed) area under the curve of y=e^(3x)−5 on the
1 answer
asked by
Mark
1,393 views
Use the Left and Right Riemann Sums with 100 rectangle to estimate the (signed) area under the curve of y=−2x+1 on the
1 answer
asked by
Mark
2,024 views
The following sum
[(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2))).(6/n)]+ ... + [(sqrt(36-((6n/n)^2))).(6/n)] is a right
1 answer
asked by
Salman
855 views
The following sum
[(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2))).(6/n)]+ ... + [(sqrt(36-((6n/n)^2))).(6/n)] is a right
0 answers
asked by
Salman
664 views