Question: Prove that [integrate {xsin2xsin[π/2*cos

Question:Prove that [integrate {x*sin2x*sin[π/2*cos x]} dx] /(2x-π) } from (0-π) = [ integrate {sin x*cos x*sin[π/2*cos x}
1. 3 answers
2. asked by Shenaya
3. 872 views
if sin2x=3sin2y,prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and
1. 7 answers
2. asked by aayush
3. 3,405 views
How do you integrate sin²x?
1. 1 answer
2. asked by Erica
3. 1,198 views
how do i integrate this? tried various methods but failed..∫ [1-sin2x]/[x-sin^2x] dx
1. 0 answers
2. asked by Arisa
3. 373 views
prove sin2x+cos2x+1 tan(pi/4+x)______________ = __________ sin2x+cos2x-1 tanx so what I did tan(x)
1. 2 answers
2. asked by Lana
3. 749 views
Prove that2sinxsiny = cos(x-y) - cos(x+y) Prove that sin2x + sin2y = 2sin(x+y)cos(x-y)
1. 1 answer
2. asked by ariza
3. 642 views
Please can anyone help with the following problems - thanks.1) Integrate X^4 e^x dx 2) Integrate Cos^5(x) dx 3) Integrate
1. 0 answers
2. asked by Febby
3. 829 views
prove that1+sin2x-cos2x / sin2x+cos2x = tanx
1. 1 answer
2. asked by Anonymous
3. 1,363 views
prove the identitysin2x-sin2y/sin2x+sin2y=tan(x-y)/tan(x+y)
1. 1 answer
2. asked by liv
3. 1,806 views
Prove that sin2x+cos2x-1/sin2x+cos2x+1=tanx
1. 1 answer
2. asked by James
3. 1,245 views

Question: Prove that [integrate {x*sin2x*sin[π/2*cos