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Prove the identity: 4x=1-8sin^2x+8sin^4x
Prove the identity:
4x=1-8sin^2x+8sin^4x
1 answer
asked by
PRELUDE
889 views
please help me on the following:
prove the identity. cos4x = 1-8sin^x2cos^2x
0 answers
asked by
John
442 views
please help me on the following:
prove the identity. cos4x = 1-8sin^x2cos^2x
1 answer
asked by
John
484 views
If we are given 8sin((pi/6)(x+2))+16=20the answers are -1 and 3 because 1/2 can be pi/6 or 5pi/6. However, if y = 10
0 answers
asked by
Ashley
431 views
Please take a look at DEVON's trig equation at 9:14
I must be missing something obvious. If the second had been 3sin 2x it would
0 answers
asked by
Reiny
685 views
Prove 8sin^5x=sinx(3-4cos(2x)+cos(4x))
2 answers
asked by
Larry Wheels
338 views
By using the identity cos2A=1-2sin^2A show that cos4x = 1-8sin^2xcos^2x
2 answers
asked by
Shauna
700 views
Verify Identity:
cos5x-cos3x=-8sin^2x(2cos^3x-cosx)
1 answer
asked by
Erik
566 views
Prove that in any triangle ABC Sin2A+Sin2B+Sin2C/SinA+SinB+SinC=8Sin(A/2)Sin(B/2)Sin(C/2)
1 answer
asked by
joel
1,059 views
8sin^4(x)
0 answers
asked by
Anonymous
381 views