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Prove that sec8A-1/sec4A-1 = tan8A/tan2A

  1. Prove thatsec8A-1/sec4A-1 = tan8A/tan2A
    1. answers icon 0 answers
    2. Kewal asked by Kewal
    3. views icon 684 views
  2. sec8A-1/sec4A-1=tan8A/tan2A
    1. answers icon 2 answers
    2. Anonymous asked by Anonymous
    3. views icon 1,011 views
  3. Prove that. (1+sec2A) (1+sec4A) (1+sec8A)=Tan8A×CotA
    1. answers icon 1 answer
    2. Bimal asked by Bimal
    3. views icon 1,036 views
  4. (1+sec 2A) (1+sec4A) (1+sec8A) = tan8AcotA
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 512 views
  5. (1+sec 2A) (1+sec4A) (1+sec8A) = tan8AcotA
    1. answers icon 2 answers
    2. Binod asked by Binod
    3. views icon 2,189 views
  6. If Tan (A+B)=1/3 and Tan(A-B)=2/5,then prove thatA.Tan2A=11/13 B.Tan2B=-1/17
    1. answers icon 2 answers
    2. Rabinprakash Dahal asked by Rabinprakash Dahal
    3. views icon 565 views
  7. If Tan (A+B)=1/3 and Tan(A-B)=2/5,then prove thatA.Tan2A=11/13 B.Tan2B=-1/17
    1. answers icon 7 answers
    2. Rabinprakash Dahal asked by Rabinprakash Dahal
    3. views icon 3,413 views
  8. If Tan (A+B)=1/3 and Tan(A-B)=2/5,then prove thatA.Tan2A=11/13 B.Tan2B=-1/17
    1. answers icon 1 answer
    2. Gunda asked by Gunda
    3. views icon 568 views
  9. Prove that(tan4A + tan2A)(1-tan²3Atan²A) = 2tan3Asec²A
    1. answers icon 2 answers
    2. Kewal asked by Kewal
    3. views icon 821 views
  10. Prove thattan2A = (sec2A+1)√sec²A-1
    1. answers icon 3 answers
    2. Kewal asked by Kewal
    3. views icon 1,167 views