Prove that sec8A-1/sec4A-1 = tan8A/tan2A

Prove thatsec8A-1/sec4A-1 = tan8A/tan2A
1. 0 answers
2. asked by Kewal
3. 723 views
sec8A-1/sec4A-1=tan8A/tan2A
1. 2 answers
2. asked by Anonymous
3. 1,048 views
Prove that. (1+sec2A) (1+sec4A) (1+sec8A)=Tan8A×CotA
1. 1 answer
2. asked by Bimal
3. 1,113 views
(1+sec 2A) (1+sec4A) (1+sec8A) = tan8AcotA
1. 1 answer
2. asked by Anonymous
3. 557 views
(1+sec 2A) (1+sec4A) (1+sec8A) = tan8AcotA
1. 2 answers
2. asked by Binod
3. 2,233 views
If Tan (A+B)=1/3 and Tan(A-B)=2/5,then prove thatA.Tan2A=11/13 B.Tan2B=-1/17
1. 2 answers
2. asked by Rabinprakash Dahal
3. 615 views
If Tan (A+B)=1/3 and Tan(A-B)=2/5,then prove thatA.Tan2A=11/13 B.Tan2B=-1/17
1. 7 answers
2. asked by Rabinprakash Dahal
3. 3,474 views
If Tan (A+B)=1/3 and Tan(A-B)=2/5,then prove thatA.Tan2A=11/13 B.Tan2B=-1/17
1. 1 answer
2. asked by Gunda
3. 622 views
Prove that(tan4A + tan2A)(1-tan²3Atan²A) = 2tan3Asec²A
1. 2 answers
2. asked by Kewal
3. 859 views
Prove thattan2A = (sec2A+1)√sec²A-1
1. 3 answers
2. asked by Kewal
3. 1,206 views