Prove that cos4x=8cos^4x-8cos^2x+1 so I'm

  1. Prove thatcos4x=8cos^4x-8cos^2x+1 so I'm guessing you begin with the left side cos4x=cos2(2x) then im kinda lost
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    2. Natash asked by Natash
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  2. Prove:cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: RS: = 4cos^2x (2cos^2x - 1) + 1 = 4 cos^2x (cos2x) + 1 LS: = cos2(2x) =
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    2. Anonymous asked by Anonymous
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  3. Prove that it is an identity: cos (4x)=8cos^4(x)-8cos^2(x)+1
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    2. Anonymus asked by Anonymus
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  4. Show that cos 4 alpha =8cos^4alpha - 8cos^2alpha + 1
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    2. Joshua asked by Joshua
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  5. Find all solutions on the interval [0.2pi)A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8cos^2(t)=3-2cos(t) All i did was move
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    2. Dan asked by Dan
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  6. If x=2cos (z) and y= sin (z), then d^2y/dx^2=?What I got -sin (z) / -8cos (z)*sin (z) simplifies to 1/8cos (z) I don't think I'm
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    2. Liam asked by Liam
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  7. Does anybody know how I can graph these on wolfram? x=cos(8cos(t))sin(t),y=sin(8cos(t))sin(t),z=cos(t).I type as it on
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    2. Anonymous asked by Anonymous
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  8. Show that Cos 4¤=8cos^4¤ - 8cos^2 + 1
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    2. Azeez asked by Azeez
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  9. Why does 1/8cos(2y+6) become 1/8cos(arcsinx/4)?
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    2. Aleks asked by Aleks
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  10. Prove the identity.6cos^2(x)-1 -12cos^4(x) +8cos^6(x)= cos^3(2x) Thanks for your help :)
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    2. Tommy asked by Tommy
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