Prove that (secx+tanx)^2=1+sinx/1-sinx Thanks in

Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 936 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
1. 0 answers
2. asked by Dave
3. 1,446 views
1/tanx-secx+ 1/tanx+secx=-2tanxso this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
1. 0 answers
2. asked by olivia
3. 1,335 views
How do I prove these trig identities?secx-cosx/tanx =sinx And 1+sinx/cosx+ cox/ 1+sinx=2secx
1. 1 answer
2. asked by Jill
3. 936 views
Trig Identitiesprove sinx+1 \ 1-sinx = (tanx+secx)^2
1. 3 answers
2. asked by ken
3. 1,193 views
My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
1. 2 answers
2. asked by Jon
3. 919 views
Prove that (secx+tanx)^2=1+sinx/1-sinxThanks in advance.
1. 1 answer
2. asked by Aliya
3. 488 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
3. 976 views
Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
1. 1 answer
2. asked by Heather
3. 784 views
Simplify (1+tanx)^2The answer is (1-sinx)(1+sinx) Here's what I do: 1 + 2tanx + tan^2x When I simplify it becomes 1 +
1. 1 answer
2. asked by AlphaPrimes
3. 651 views