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Prove each idenity. 1+1/tan^2x=1/sin^2x 1/cosx-cosx=sinxtanx
Prove each idenity.
1+1/tan^2x=1/sin^2x 1/cosx-cosx=sinxtanx 1/sin^2x+1/cos^2x=1/sin^2xcos^2x 1/1-cos^2x+/1+cosx=2/sin^2x and
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asked by
Rani
619 views
I'm sorry to double post; I don't want to seem impatient, but I really need help with this.
Prove each idenity.
14 answers
asked by
Rani
826 views
Solve this equation fo rx in the interval 0<=x<=360
3sinxtanx=8 I would do it this way: sinxtanx = 8/3 sinx(sinx/cosx)=8/3
0 answers
asked by
Edward
975 views
(cotxsec2x - cotx)/ (sinxtanx + cosx) = sinx
prove. i keep getting (if i start from the left side) = cosx instead of sinx please
1 answer
asked by
Spencer
1,409 views
Trigonometric Identities
Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
0 answers
asked by
Dave
1,446 views
I can't seem to prove these trig identities and would really appreciate help:
1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1:
1 answer
asked by
Heather
1,275 views
I need help proving this identity
1/cosx - cosx = sinxtanx
1 answer
asked by
Anonymous
418 views
I need help proving this identity
1/cosx - cosx = sinxtanx
5 answers
asked by
Anonymous
679 views
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
asked by
Anonymous
1,069 views
prove the identity
(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
0 answers
asked by
JungJung
910 views