Prove each idenity. 1+1/tan^2x=1/sin^2x 1/cosx-cosx=sinxtanx

Prove each idenity.1+1/tan^2x=1/sin^2x 1/cosx-cosx=sinxtanx 1/sin^2x+1/cos^2x=1/sin^2xcos^2x 1/1-cos^2x+/1+cosx=2/sin^2x and
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2. asked by Rani
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I'm sorry to double post; I don't want to seem impatient, but I really need help with this.Prove each idenity.
1. 14 answers
2. asked by Rani
3. 899 views
Solve this equation fo rx in the interval 0<=x<=3603sinxtanx=8 I would do it this way: sinxtanx = 8/3 sinx(sinx/cosx)=8/3
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2. asked by Edward
3. 1,041 views
(cotxsec2x - cotx)/ (sinxtanx + cosx) = sinxprove. i keep getting (if i start from the left side) = cosx instead of sinx please
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2. asked by Spencer
3. 1,459 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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2. asked by Dave
3. 1,514 views
I can't seem to prove these trig identities and would really appreciate help:1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1:
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2. asked by Heather
3. 1,341 views
I need help proving this identity1/cosx - cosx = sinxtanx
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2. asked by Anonymous
3. 457 views
I need help proving this identity1/cosx - cosx = sinxtanx
1. 5 answers
2. asked by Anonymous
3. 724 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
2. asked by Anonymous
3. 1,156 views
prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
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2. asked by JungJung
3. 965 views