Prove: sin2x*sinx/2cosx + cos^2 0

Prove:sin2x*sinx/2cosx + cos^2 0 = 1
1. 2 answers
2. asked by S
3. 510 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
1. 0 answers
2. asked by shan
3. 978 views
prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
1. 0 answers
2. asked by JungJung
3. 912 views
Prove the identity((Cos²x - sin²x) ÷ (cosx + sinx) ) + sinx
1. 1 answer
2. 136 views
Given that y=sin x ln (x+1),prove that(d^2 y)/(dx^2 )+y=2cosx/(x+1)-sinx/(x+1)^2
1. 1 answer
2. asked by lydiah
3. 454 views
Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 938 views
Prove the following functions:(sinx+sin2x)/(1+cosx+cos2x)=tan x (cos3x/sinx)+(sin3x/cosx)=2cot2x tan2x=(2/cotx-tanx) theses are
1. 2 answers
2. asked by jared
3. 1,091 views
Prove the identity(sinx+cosx)^2 = 1+sin2x Thank you
1. 1 answer
2. asked by Bear
3. 445 views
Having trouble verifying this identity...cscxtanx + secx= 2cosx This is what I've been trying (1/sinx)(sinx/cosx) + secx = 2cosx
1. 2 answers
2. asked by Alex
3. 677 views
prove identitySin2x - sinx/cosx + cos2x= sinx/cosx + 1
1. 1 answer
2. asked by Matthew
3. 1,178 views