Prov that 1-sin2X/sinX-cosX=sinX-cosX

Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
2. asked by Anonymous
3. 1,072 views
Verify the identity:tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx
1. 0 answers
2. asked by Ashley
3. 1,245 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
3. 978 views
Prov that 1-sin2X/sinX-cosX=sinX-cosX
1. 1 answer
2. asked by Neo
3. 469 views
I need to prove that the following is true. Thanks(cosx / 1-sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds
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2. asked by abdo
3. 994 views
prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
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2. asked by JungJung
3. 912 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1. 4 answers
2. asked by Anonymous
3. 1,949 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1. 1 answer
2. asked by Anonymous
3. 1,348 views
If y=3/(sinx+cosx) , find dy/dxA. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
1. 1 answer
2. asked by Anonymous
3. 664 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
1. 0 answers
2. asked by Dave
3. 1,447 views