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Oxalic acid (H2C2O4) can be used to remove rust according

Oxalic acid (H2C2O4) can be used to remove rust according to the following balanced equation:Fe2O3 + 6H2C2O4 --> 2Fe(C2O4)33-
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2. asked by amber
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Oxalic acid (H2C2O4) can be used to remove rust according to the following balanced equation:Fe2O3 + 6H2C2O4 --> 2Fe(C2O4)33-
1. 4 answers
2. asked by amber
3. 1,076 views
What is the mole of oxalic acid?Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O *Moles of oxalic acid dihydrate is 0.032 mole. *
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2. asked by Ivy
3. 1,530 views
What is the mole of oxalic acid?Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O *Moles of oxalic acid dihydrate is 0.032 mole. *
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2. asked by Ivy
3. 1,264 views
1. A sample of oxalic acid (H2C2O4, with two acidic protons), of volume 46.56 mL was titrated to the stoichiometric point with
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2. asked by Angelica
3. 706 views
How do you find the Ka1 and Ka2 of oxalic acid when it is in a solution that is 1.05 M H2C2O4 and has a pH of 0.67. [C2O4^2-] =
1. 1 answer
2. asked by Erika
3. 2,259 views
100mL of oxalic acid (H2C2O4) requires 35mL of 0.04M KMnO4 to titrate it to the endpoint. calculate the molarity of the oxalic
1. 3 answers
2. asked by aisha
3. 1,770 views
100mL of oxalic acid (H2C2O4) requires 35mL of 0.04 M KMnO4 to titrate it to the endpoint. calculate the molarity of the oxalic
1. 1 answer
2. asked by Wesley
3. 541 views
20.5 mL of oxalic acid,H2C2O4 were titrated with 0.800 M solution of lithium hydroxide. It took 40.0 mL of the base to reach the
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2. asked by Ari
3. 905 views
oxalic acid, h2c2o4, is a weak acid capable of providing two H3O+ ions.ka=.059 k2=6.4E-5 the [h3o]+ in a .38 M solution of
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2. asked by anonymous
3. 1,219 views