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Naoh+h2so4--------h20 +na2so4 Now the question
When solutions of H2SO4 and NaOH react, the balanced molecular equation is: H2SO4 (aq) + 2 NaOH(aq) Na2SO4(aq) + 2 H2O (I)
How
2 answers
asked by
Val
2,351 views
In a silphuric acid (H2SO4)-Sodium Hydroxide (NaOH) acid-base titration, 17.3mL of 0.126M NaOH is needed to neutralize 25mL of
2 answers
asked by
Dawn
1,235 views
What mass of Na2so4 is produced if 49g of h2so4 react with 80g of Naoh
Naoh + h2so4 Na2so4 + 2h2o
1 answer
asked by
Sadiiq
95 views
For
H2SO4 + 2NaOH = 2H2O + Na2SO4 n(H2SO4) = 9.65g/98g/mol = 0.098 n(NaOH) = 6.10g/40g/mol = 0.15 mol 1 mole of H2SO4 is = to 1
0 answers
asked by
Anonymous
1,058 views
What mass of Na2so4 is produced if 49g of h2so4 react with 80g of Naoh
2Naoh + h2so4 Na2so4 + 2h2o
1 answer
asked by
Sadiiq
95 views
NaOH(s)+ H2SO4(aq)=Na2SO4(aq) + H2O(l)
Consider the unbalanced equation above.A 0.900 g sample of impure NaOH was dissolved in
2 answers
asked by
Tiffany
1,652 views
Consider the reaction of sulfuric acid, H2SO4, with sodium hydroxide, NaOH.
H2SO4(aq) + 2 NaOH(aq) -> 2H2O(l) + Na2SO4(aq).
1 answer
asked by
Mandy
1,468 views
Calculate the molarity of the H2SO4 solution if 17.45 mL of NaOH was necessary to reach the endpoint of titration. The molarity
1 answer
asked by
Audrey
1,379 views
When 25.3 mL of 0.100 M NaOH was reacted with 18.8 mL of H2SO4 of unknown molarity, the final solution was 0.029207 M in H2SO4.
2 answers
asked by
Haley
621 views
Naoh+h2so4--------h20 +na2so4
Now the question is what number of moles of naoh require to neutralize 1 mole of h2sor.
2 answers
asked by
Anonymous
500 views