NH4HS(s)-> NH3(g) + H2S(g) What

  1. NH3+H2S-->NH4HS<-- Kc=400 at 35 Celsius what mass of NH4HS will be present at equilbrium? My work NH3 H2S NH4HS initial 2 mol 2
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    2. Anonymous asked by Anonymous
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  2. At 23°C, Kp = 0.075 for the equilibrium:NH4HS (s) ↔ NH3 (g) + H2S (g) A sample of solid NH4HS is placed in a closed vessel
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    2. Nicole asked by Nicole
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  3. NH4HS(s )<=>NH3(g)+ H2S(g) ∆H = +93 kilojouesThe equilibrium,above is established by placing solid NH4HS in an evacuated
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    2. Paul asked by Paul
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  4. NH4HS(s) NH3(g) + H2S(g) ∆H_ = +93 kilojoulesThe equilibrium above is established by placing solid NH4HS in an evacuated
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    2. Paul asked by Paul
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  5. A sample of NH4HS(s) is placed in a 2.61 −L flask containing 0.120 mol NH3(g).NH4HS(s)⇌NH3(g)+H2S(g) Kp=0.108 at 25∘C Part
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    2. K asked by K
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  6. A sample of NH4HS(s) is placed in a 2.61 −L flask containing 0.120 mol NH3(g).NH4HS(s)⇌NH3(g)+H2S(g) KP=0.108 at 25∘C What
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    2. Jasper asked by Jasper
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  7. A sample of NH4HS(s) is placed in a 2.57 −L flask containing 0.140 mol NH3(g).NH4HS(s)⇌NH3(g)+H2S(g)KP=0.108at25∘C What
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    2. Steve asked by Steve
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  8. Ammonium hydrogrn sulfide decomposes according to the reaction.NH4HS(s) <----> NH3(g) + H2S(g) If 55.0g of solid NH4HS is placed
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    2. Starla asked by Starla
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  9. Help please, What is the minimum mass of NH4HS that must be added to the 5.00-L flask when charged with the 0.350g of pure
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    2. Brandon asked by Brandon
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  10. I would really appreciate some help on this problem. =)At 218 C, Kc = .00012 for the equilibrium NH4HS(s)<==> NH3(g)+ H2S(g)
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    2. Jenn asked by Jenn
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