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NH4HS(s)-> NH3(g) + H2S(g) What
NH3+H2S-->NH4HS
<-- Kc=400 at 35 Celsius what mass of NH4HS will be present at equilbrium? My work NH3 H2S NH4HS initial 2 mol 2
3 answers
asked by
Anonymous
3,823 views
At 23°C, Kp = 0.075 for the equilibrium:
NH4HS (s) ↔ NH3 (g) + H2S (g) A sample of solid NH4HS is placed in a closed vessel
2 answers
asked by
Nicole
6,190 views
NH4HS(s )<=>NH3(g)+ H2S(g) ∆H = +93 kilojoues
The equilibrium,above is established by placing solid NH4HS in an evacuated
1 answer
asked by
Paul
829 views
NH4HS(s) NH3(g) + H2S(g) ∆H_ = +93 kilojoules
The equilibrium above is established by placing solid NH4HS in an evacuated
1 answer
asked by
Paul
1,730 views
A sample of NH4HS(s) is placed in a 2.61 −L flask containing 0.120 mol NH3(g).
NH4HS(s)⇌NH3(g)+H2S(g) Kp=0.108 at 25∘C Part
3 answers
asked by
K
707 views
A sample of NH4HS(s) is placed in a 2.61 −L flask containing 0.120 mol NH3(g).
NH4HS(s)⇌NH3(g)+H2S(g) KP=0.108 at 25∘C What
3 answers
asked by
Jasper
1,232 views
A sample of NH4HS(s) is placed in a 2.57 −L flask containing 0.140 mol NH3(g).
NH4HS(s)⇌NH3(g)+H2S(g)KP=0.108at25∘C What
1 answer
asked by
Steve
748 views
Ammonium hydrogrn sulfide decomposes according to the reaction.
NH4HS(s) <----> NH3(g) + H2S(g) If 55.0g of solid NH4HS is placed
1 answer
asked by
Starla
1,893 views
Help please, What is the minimum mass of NH4HS that must be added to the 5.00-L flask when charged with the 0.350g of pure
4 answers
asked by
Brandon
3,399 views
I would really appreciate some help on this problem. =)
At 218 C, Kc = .00012 for the equilibrium NH4HS(s)<==> NH3(g)+ H2S(g)
2 answers
asked by
Jenn
2,124 views