Ask a New Question

Mols benzoic acid = 12.2g/122.12g

Mols benzoic acid = 12.2g/122.12g = 0.0999Int. Concentration of Benzoic acid = 0.0999 mol/ 0.500L = 0.1998 M Ka = 6.3 x 10-5 =
1. 1 answer
2. asked by Jake
3. 454 views
The ethyl acetate solution containing the mixture used in this experiment had a concentration of 20.0 g/L of benzoic acid. The
1. 1 answer
2. 113 views
Enough water is added to 0.35 g of benzoic acid to make 1000 mL of solution. What is the pH?Ionization Constant for Benzoic Acid
1. 2 answers
2. asked by LT
3. 928 views
breifly describe how you would separate a mixture of sand and benzoic acid(benzoic acid is soluble in hot water) to obtain pure
1. 0 answers
2. asked by dee
3. 708 views
A 0.25 mol/L solution of benzoic acid, KC7H5O2 and antiseptic also used as a food preservative, has a pH of 2.40. Calculate the
1. 1 answer
2. asked by Sarah
3. 615 views
How many mols of benzoic acid are soluble in 125 mL of water at room temperature.
1. 1 answer
2. asked by Amy
3. 500 views
ReferencesChapter 17: EOC Assume you dissolve 0.178 g of the weak acid benzoic acid, , in enough water to make mL of solution
1. 1 answer
2. asked by Anonymous
3. 631 views
When 200 mL of an aqueous benzoic acid solution were extracted with 30 mL of ethyl actetate 45% of the benzoic acid were
1. 0 answers
2. asked by Nick
3. 665 views
If 20.5 mL of a 5.256 M solution of benzoic acid is used in an experiment similar to experiment 4, how many grams of benzoic
1. 1 answer
2. asked by alice
3. 504 views
Given that the Ka of benzoic acid is 6.50 x 10-5, how would one prepare 0.500 L of a benzoic acid/sodium benzoate buffer of a
1. 2 answers
2. asked by Nadine
3. 782 views