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M=sina+cosa N=seca+coseca M^2/2M^2-N^2=cosa^2/2-2sina^2-coseca^2
M=sina+cosa
N=seca+coseca M^2/2M^2-N^2=cosa^2/2-2sina^2-coseca^2
1 answer
asked by
Arshad
147 views
prove that the following are identity
1. (cotA+cosecA-1)/(cotA-cosecA+1)=cosecA+cotA 2. (sinA-cosA+1)/(sinA+cosA-1)=
0 answers
asked by
Anonymous
564 views
sinA+cosA=p ,secA+cosecA=q (cosA)^2/[2-2(sinA)^2-(cosecA)^2]=p^2/(2(p^2)-q^2
0 answers
asked by
yousuf
472 views
sinA+cosA=p ,secA+cosecA=q (cosA)^2/[2-2(sinA)^2-(cosecA)^2]=p^2/(2(p^2)-q^2
2 answers
asked by
yousuf
1,911 views
sinA+cosA=p and secA+CosecA=q
then show that q[p^2-1]=2p
4 answers
asked by
kumar
2,814 views
Hello I am having trouble with proving this:
sinA/secA+secA/cscA = tan(A)(2-sin^2(A)) So far I've gotten SinA/(1/cosA) +
1 answer
asked by
Jimbo
798 views
Prove that. √seca+2sina/seca-2sina=Sina+cosa/sina-cosa
2 answers
asked by
Aditya
987 views
prove that :cosA-sinA+1/cosA+sinA-1=cosecA+cotA
2 answers
asked by
rajan
714 views
Hi, can someone give me the answer to this question:
secA-tanA=1/4. Find cosA I got: CosA=4(1-sinA) Is my answer good? Now
2 answers
asked by
Shym
925 views
I need to prove that the following is true. Thanks.
csc^2(A/2)=2secA/secA-1 Right Side=(2/cosA)/(1/cosA - 1) =
0 answers
asked by
Dirk
963 views