List two different equations for

e. What two equations from those above would form a system with one solution?You can list the 2 equations here AND give the
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1. y=5x–4: y=5x–42. y=–2x+3: y=–2x+3 3. y=3x+1: y=3x+1 4. 2y=6x+2: y=3x+1 5. y–5x=+2: y = 5x + 2 6. y–4x+1=0: y=4x-1
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1. y=5x–4: y=5x–42. y=–2x+3: y=–2x+3 3. y=3x+1: y=3x+1 4. 2y=6x+2: y=3x+1 5. y–5x=+2: y = 5x + 2 6. y–4x+1=0: y=4x-1
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2. 20 views
For the function f whose graph is given, state the following(a) lim x → ∞ f(x) (b) lim x → −∞ f(x) (c) lim x → 1
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2. asked by Anonymous
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1. y=5x–4: y=5x–42. y=–2x+3: y=–2x+3 3. y=3x+1: y=3x+1 4. 2y=6x+2: y=3x+1 5. y–5x=+2: y = 5x + 2 6. y–4x+1=0: y=4x-1
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2. 28 views
public static void mystery(ArrayList<Integer>list) {for (int i = 1; i < list.size(); i += 2) { if (list.get(i - 1) >=
1. 1 answer
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public static void mystery(ArrayList<Integer>list) {for (int i = 1; i < list.size(); i += 2) { if (list.get(i - 1) >=
1. 1 answer
2. 109 views
public static void mystery(ArrayList<Integer>list) {for (int i = 1; i < list.size(); i += 2) { if (list.get(i - 1) >=
1. 1 answer
2. 96 views
public static void mystery(ArrayList<Integer>list) {for (int i = 1; i < list.size(); i += 2) { if (list.get(i - 1) >=
1. 1 answer
2. 97 views
public static void mystery(ArrayList<Integer>list) {for (int i = 1; i < list.size(); i += 2) { if (list.get(i - 1) >=
1. 1 answer
2. 106 views