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Let f(t)=t\sqrt{4-t} on the interval
Given f(x)=x^4(2x^2-15). On what interval(s) is the graph of f concave upwards?
A. (0, sqrt(3)) B. (-sqrt(3), 0) C. (-sqrt(3), 0)
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asked by
Sarah
919 views
Find the domain of vector function r (t)= sqrt(4 - t ^ 2) i + sqrt(t) j - 2/(sqrt(1+t)) k. State your answer in interval
1 answer
asked by
Ken
159 views
Given f(x)=4+3/x find all values of c in the interval (1,3) that satisfy the mean value theorem.
A. 2 B. Sqrt(2) C. Sqrt(3) D.
1 answer
asked by
Sarah
781 views
Find the domain of the vector function r(t)= sqrt(4 - t ^ 2) i + sqrt(t) j - 2 / (sqrt(1 + t)) k.
answer in interval notation
1 answer
asked by
Ken
185 views
The domain of the function $f(x) = \sqrt{25-x^2}+\sqrt{x-2} + \frac{1}{\sqrt{1 - x}}$ is an interval of what width?
1 answer
asked by
alice
90 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1 answer
asked by
Alexa
3,199 views
I need to find the exact solution to:
2sin2x = sqrt(x)on the interval (0,pi) This is how I started it, but I don't think it's
0 answers
asked by
Jen
715 views
sqrt 6 * sqrt 8
also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So you can see the steps — sqrt 6 * sqrt 8 = sqrt 48 sqrt 7 *
0 answers
asked by
Tina
723 views
2sin(2theta) + sqrt(3) = 0
interval (0,2pi) How do I solve this? I thought about maybe subtracting the sqrt(3) from both sides,
1 answer
asked by
Hannah
1,303 views
Find the domain of the function $$f(x) = \sqrt{x-2 \sqrt[3]{x-3}}.$$ Express your answer in interval notation.
1 answer
asked by
alice
100 views