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LOG(base5)(3/5)+3log(base5)(15/2)-log(base5)(81/8)
Hi, same ques. again
1/3log(base5) 3x + log(base5) 4=3 If the starting is this: log(base5)3x^1/3+log(base5)4=3 What would be the
2 answers
asked by
Jack
252 views
Need help with these:
Write the expression as a logarithm of a single quality. a) 3log[base5](a) + 4log[base5](b) -
2 answers
asked by
Tom
616 views
Find A so that
5log(base5)16807 − 3log(base5)7 = log (base5)A I don't even know how to start this one...should I remove the 5
3 answers
asked by
Ann
525 views
I got this question, and found what I believe to be the solution, but want it confirmed.
I started with: log[base5](2x+1) +
3 answers
asked by
anonymous
950 views
1/3log(base5) 3x + log(base5) 4=3
what I meant is: 1/3=one-third ,log5= log(base5)
1 answer
asked by
Jack
258 views
LOG(base5)(3/5)+3log(base5)(15/2)-log(base5)(81/8)
4 answers
asked by
olaide
1,651 views
Hi guys,
how to solve this: 1/3 log(base5) 3x + log(base5) 4=3 Please help math hero
3 answers
asked by
Jack
262 views
Solve for x:
log base5 (4x) + log base5 (x) = log base5 (64)
1 answer
asked by
Aly
539 views
Can someone help me find the value of B in this expression????
log 64 = Blog 4 5 5 Grrr... sorry about that. Here's the
1 answer
asked by
UnstoppableMuffin
634 views
how do i solve these two problems?
3log(base5)^(x^2+9)-6 = 0 log(base8)^(n-3) + log(base8)^n+4)= 1 can you tell me step by step
3 answers
asked by
Ana
785 views