Integrate dx/(sqrt(x^2+16)). I have no

Please do help solve the followings1) Integrate e^4 dx 2) Integrate dx/sqrt(90^2-4x^2) 3) Integrate (e^x+x)^2(e^x+1) dx 4)
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Integrate: 1/(x-sqrt(x+2) dxI came up with: (2/3)(2*ln((sqrt(x+2))-2)+ln((sqrt(x+2))-1)) but it keeps coming back the wrong
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2. asked by COFFEE
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Calc length of arc of y=ln(x) from x=1 to x=2---- So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x =
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Question: ∫(x^2)/sqrt(x^2+1)u=x^2+1 , x^2= u-1, du=2xdx ∫(u-1)/sqrt(u) , expand ∫u/sqrt(u) - 1/sqrt(u) Integrate:
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2. asked by Liam
3. 579 views
Integrate: dx/sqrt(x^2-9)Answer: ln(x + sqrt(x^2 - 9)) + C I'm getting the wrong answer. Where am I going wrong: Substitute: x =
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2. asked by mathstudent
3. 841 views
Please can anyone help with the following problems - thanks.1) Integrate X^4 e^x dx 2) Integrate Cos^5(x) dx 3) Integrate
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2. asked by Febby
3. 810 views
Find arc length of y=logx from x=1 to x=2.dy/dx)^2=1/x^2 arc length=Int of [sqrt(1+1/x^2)]dx =Int of [sqrt(1+x^2)/x^2] =Int of
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2. asked by MS
3. 924 views
Find arc length of y=logx from x=1 to x=2.dy/dx)^2=1/x^2 arc length=Int of [sqrt(1+1/x^2)]dx =Int of [sqrt(1+x^2)/x^2] =Int of
1. 3 answers
2. asked by MS
3. 460 views
Integrate sqrt(x^2 + 1) dx over [0,2*pi]I can substitute u=arctan x to get: Integrate (sec u)^3 du over [0,arctan(2*pi)] From
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2. asked by Parker
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Integrate:Indefinite integral of [(sqrt(x))-1]^2 / [sqrt(x)] dx
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2. asked by Anonymous
3. 401 views