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In the equation y=4cos 6x,

Write an equation for simple harmonic motion, given that the amplitude equals 4 inches and the period equals 2 seconds and the
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What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
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Which equation would the table of values represent? 0, 3 pi over 2, 3 pi, 9 pi over 2, 6 pi. 0, 4, 0, -4, 0 (1 point) Responses
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a) Express f(theta) = 4cos theta - 6sin theta in the form r cos(theta + alpha)b) Hence find the general solution of the equation
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solve the equation 4cos^2x-1=0
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solve the equation 4cos^2x-1=0
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solve the equation in the interval from 0 to 2π, 4cos(t)=3
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solve the equation1+4sin(x)=4cos^2(x)
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Sketch the region enclosed by the curves given below. Decide whether to integrate with respect to x or y. Then find the area of
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find all solutions of the equation 4cos^2x-4cosx+1=0
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