In right triangle ABC, sinA=5/13.

Triangle HAV has <H = 124, a=8.5mm, and h=7.2mmHow many solutions are there? What I attempted: SinH/h=SinA/a Sin124/7.2=SinA/8.5
1. 2 answers
2. asked by AlphaPrimes
3. 644 views
Please help with this one. I've worked it out in so many ways and can't tell what's correct.sinA sinA ----- - ------ 1+sinA
1. 0 answers
2. asked by Jasmine
3. 694 views
Hi, can someone give me the answer to this question:secA-tanA=1/4. Find cosA I got: CosA=4(1-sinA) Is my answer good? Now
1. 2 answers
2. asked by Shym
3. 925 views
In any angle ABC prove that the perimeter = a/Sin A(Sin A + Sin B + Sin C)Start with perimeter = a+b+c but b= aSinB/sinA and c=
1. 0 answers
2. asked by Anonymous
3. 534 views
Hello I am having trouble with proving this:sinA/secA+secA/cscA = tan(A)(2-sin^2(A)) So far I've gotten SinA/(1/cosA) +
1. 1 answer
2. asked by Jimbo
3. 798 views
find all solutions in the interval [0,2 pi)sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 x Since sin (a+b) = sina cosb + cosb
1. 1 answer
2. asked by lauren
3. 846 views
Verify/prove the following:(sinA+tanA)/(1+secA) = sinA ______________________________ tanu = 1+sinu-cos^2u/cosu(1+sinu)
1. 1 answer
2. asked by Kid
3. 729 views
Prove that [sinA/(1-cosA)-(1-cosA)/sinA]*[cosA/(1+sinA)+(1+sinA)/cosA]=4cosecAI the second part as 2 secA
1. 1 answer
2. asked by Agastya
3. 733 views
Consider a non-right triangle. a=39 b=25 c = 24.(a,b,c are the sides) Find A,B,C. (these are the degrees of the triangle)I know
1. 1 answer
2. asked by Student (UCI)
3. 482 views
Find the area of a triangle if the sides of the triangle have the lengths 849mi, 930mi, and 1301mi.Here's my work: a=849 b=930
1. 5 answers
2. asked by Alexis
3. 449 views