In modern hopitals, everything possible

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In modern hopitals, everything possible is done to prevent mistakes resultin from human (fallibility ,uncertainty)Answer -
1. 1 answer
2. asked by cici
3. 450 views
Using l'hopitals rule, evaluate the following:Lim x-->infinity Inx/2(x)^1/2 Limx-->0 (1/x - 1/e^x -1) I tried both multiple
1. 0 answers
2. asked by Maya
3. 496 views
without using l'hopitals rule.limit of h goes to 0 of [ sin 2((3*pi/8)+h)) - sin (3*pi/4)] / h
1. 1 answer
2. asked by elan
3. 266 views
Find the limit. Use L'Hopitals Rule if necessary.lim (x^2+3x+2)/(x^2+x) x -> 0
1. 1 answer
2. asked by Britt
3. 532 views
Stuck... can't seem to use l'hopitals, nor can I use logrithmic differentiation...lim (e^(2x)+ x)^(1/3x) x->0+ Thank you so much
1. 6 answers
2. asked by Joey
3. 388 views
find the limit of lim sin(x-1)/(x^2 + x - 2) x->1without using l'hopitals rule
1. 3 answers
2. asked by khela
3. 756 views
lim as x approaches 0(e^4x-1)/sin(2x) I know you use L-hopitals rule and I know the answer is 2 but I keep getting 1. Can
1. 2 answers
2. asked by Anonymous
3. 999 views
Can you please help me get the solution to this limit without using squeeze theorem and l'hopitals rulelim x to 0 of x^3
1. 1 answer
2. asked by Liv
3. 467 views
find the limit as x approaches 0 of the function: (e^x.sinx)/xwithout using hopitals rule
1. 1 answer
2. asked by eddie
3. 448 views
I am studying for a final exam and in our review packet we have this question, which I am having trouble with:lim (x-->0)
1. 1 answer
2. asked by Jenna
3. 617 views