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If sinA + sinB =
Given a = 31.5, b = 51.8, A = 33 degrees, find the value of c in triangle ABC.
bsinA = 51.8sin33 = 28.21 -> bsinA < a < b so
1 answer
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K
1,090 views
SinA + sinB/sinA - sinB= tanA+B/2cotA-B/2
1 answer
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sandy
1,101 views
Prove That Sin2A+ Sin2B +SIN2C/sinA+SINB+SINC=8sinA/sinB/2COSC/2
1 answer
asked by
Joel
979 views
If A+B+C=^(^=180) prove that
sinA + sinB - sinC = 4sinA/2 sinB/2 cosC/2
2 answers
asked by
ody
2,042 views
Prove: 1+(TanA/SinB)^2/1+(TanA/SinC)^2 = 1+(SinA/TanB)^2/1+(SinA/TanC)^2
4 answers
asked by
Rabin
3,722 views
1+(tanA/sinB)²/1+(tanA/sinC)²=1+(sinA/tanB)²/1+(sinA/tanC)²
2 answers
asked by
Avinash ray
202 views
Let P=(cosA sinA)
(sinA cosA) Q=(cosB sinA) (sinB cosA) show that PQ=(cosA(A-B) sin(A B)) (sinA(A B) cos(A-B))
0 answers
asked by
James
700 views
A+B=90 then sina sinb=
1 answer
asked by
anya
643 views
sinA.sin(B – C) + sinB.sin(C – A) + sinC.sin(A – B) = 0
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sinA.sin(B – C) + sinB.sin(C – A) + sinC.sin(A –B)
65 views
If A+B=90° then what is the range of SinA•SinB
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asked by
meet
794 views