If g(x)=cos2x. Find g(pi/2) and

  1. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
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    2. Brian asked by Brian
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  2. Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
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    2. Maria asked by Maria
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  3. Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
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    2. Anonymous asked by Anonymous
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  4. find all solutions of the equation 2sin x cos2x-cos2x=0 over the interval 0<x<=pi
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    2. owo asked by owo
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  5. Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
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    2. sh asked by sh
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  6. Find the derivative of y with respect to x:y=(1+cos²x)^6 y'=6(1+cos²x)^5 How do you derive inside the brackets? The answer
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    2. sh asked by sh
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  7. If sinx = 1/4 Find the exact value of cos2xI used the formula for double angle identities : cos2x = 1-2sin^2x and got the answer
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    2. Don asked by Don
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  8. sinx = 4/5 and x terminates in Quadrant IIFind sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?
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    2. Amandeep asked by Amandeep
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  9. Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
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    2. Maggie asked by Maggie
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  10. Prove that cos3x/cosx-cos6x/cos2x=2(cos2x-cos4x)
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    2. Joel asked by Joel
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