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If g(x)=cos2x. Find g(pi/2) and
Solve the equation of the interval (0, 2pi)
cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
4 answers
asked by
Brian
813 views
Find all solutions to the equation in the interval [0, 2pi)
cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
1 answer
asked by
Maria
1,651 views
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).
8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
5 answers
asked by
Anonymous
861 views
find all solutions of the equation 2sin x cos2x-cos2x=0 over the interval 0<x<=pi
4 answers
asked by
owo
2,226 views
Solve identity,
(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
3 answers
asked by
sh
770 views
Find the derivative of y with respect to x:
y=(1+cos²x)^6 y'=6(1+cos²x)^5 How do you derive inside the brackets? The answer
2 answers
asked by
sh
653 views
If sinx = 1/4 Find the exact value of cos2x
I used the formula for double angle identities : cos2x = 1-2sin^2x and got the answer
1 answer
asked by
Don
887 views
sinx = 4/5 and x terminates in Quadrant II
Find sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?
1 answer
asked by
Amandeep
1,769 views
Hello! Can someone please check and see if I did this right? Thanks! :)
Directions: Find the exact solutions of the equation in
1 answer
asked by
Maggie
865 views
Prove that cos3x/cosx-cos6x/cos2x=2(cos2x-cos4x)
2 answers
asked by
Joel
1,178 views