Ask a New Question
Menu

If f''(x)=-4sin2x, f(0)=0 and f'(0)=2,

  1. If f''(x)=-4sin2x, f(0)=0 and f'(0)=2, find the value of f(pi/4).
    1. answers icon 1 answer
    2. skylor asked by skylor
    3. views icon 425 views
  2. lim (4sin2x - 3x cos5x)/(3x/2 +(x^2)cscx )x->0
    1. answers icon 1 answer
    2. mo asked by mo
    3. views icon 588 views
  3. ʃ (4sin²x cos²×/sin2x cos2x)dxPLEASE HELP!!
    1. answers icon 1 answer
    2. INTEGRAL asked by INTEGRAL
    3. views icon 851 views
  4. Can someone please check my answers and help me with the last question!1. Solve sin2xcos2x = 4sin2x on the interval [0, 2pi] 0,
    1. answers icon 8 answers
    2. mysterychicken asked by mysterychicken
    3. views icon 652 views
  5. Please help..ʃ (4sin²x cos²×/sin 2x cos 2x)dx That's integration of (4sin^2x cos^2x over sin 2x cos 2x) dx i've got it from
    1. answers icon 2 answers
    2. INTEGRAL asked by INTEGRAL
    3. views icon 1,411 views
  6. ʃ (4sin²x cos²×/sin2x cos2x)dxi've got it from the book and it has an answer from the back page of the book but i want to
    1. answers icon 0 answers
    2. INTEGRAL asked by INTEGRAL
    3. views icon 641 views
  7. Trigonometry Questions1. Solve the equation sin2x+1=-2sinx for 0≤x≤2π 2. Solve the equation 7sin2x-4sin2x/cosx=-1 where
    1. answers icon 3 answers
    2. john asked by john
    3. views icon 964 views