If cosx=sqrt{3}/2 and −pi/2

verify for sqrt(1-cosx)= sin/sqrt(1+cosx).I multiplied the right side by sqrt(1-cosx) and got sqrt(1-cosx)= sin*sqrt(1-cosx),
1. 3 answers
2. asked by unknown
3. 1,126 views
Find the exact value of sinx/2 if cosx = 2/3 and 270 < x < 360.A)1/3 B)-1/3 C)sqrt 6/6 D)-sqrt 6/6 C, since I KNOW cosx is
1. 4 answers
2. asked by Jon
3. 958 views
For f(x) = 2sinx + (sinx)^3 + tanx find f'(pi/3). Ok, so what I tried was...f'(x) = 2cosx + cosx(3(sinx)^2) + (sinx/cosx) pi/3 =
1. 1 answer
2. asked by Mel
3. 661 views
The equation 2sinx+sqrt(3)cotx=sinx is partially solved below.2sinx+sqrt(3)cotx=sinx sinx(2sinx+sqrt(3)cotx)=sinx(sinx)
1. 7 answers
2. asked by girly girl
3. 5,612 views
Find 2 cos(x/2) sin(x/2) when x = -π/6.I know that cos(x/2) = +- sqrt(1-cosx)/2 and sin(x/2) = +- sqrt(1+cosx)/2, but how to
1. 5 answers
2. asked by Denis
3. 566 views
(Sin^3x-cos^3x)/(sinx-cosx) – cosx/sqrt(1+cot^2x)-2tanxcotx=-1 where x∈(0,2pi)general value of x.
1. 1 answer
2. asked by anil jha
3. 2,011 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
2. asked by Anonymous
3. 1,069 views
For the following question, we need to find the length of the polar curve:r= 2/(1-cosx) from pi/2 </= x </= pi dr/dx=
1. 1 answer
2. asked by Jenna
3. 702 views
hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
1. 0 answers
2. asked by elle
3. 711 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1. 1 answer
2. asked by Alexa
3. 3,195 views