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If S=1/2^2cos1 + 1/cos1¤cos2+1/2^3 cos1
If S=1/2^2cos1 + 1/cos1¤cos2+1/2^3 cos1 ¤cos2¤cos2^2 + .......... upto 10 terms . If S= sina(cotb-cotc) where a,b,c€N Then
2 answers
asked by
piyush yadav
1,049 views
y = 2[cos1/2(f1 - f2)x][cos1/2(f1 + f2)x]
let f1 = 16 let f2 = 12 therefore y = 2[cos1/2(16 - 12)x][cos1/2(16 + 12)x] y =
1 answer
asked by
Lola
697 views
What Is The closure of the set {cos1,cos2,cos3,cos4,...} under usual topology????
1 answer
asked by
Itrat Abbas Mirza
458 views
Is The Set {cos1,cos2,cos3,cos4,...} under usual topology closed??? whatbiis its closure????
0 answers
asked by
Itrat abbas mirza
485 views
If the radius of a circle is 3960
the angle is 1.59 the arc length is 110 how would I find the hypotenuse? I think it is
1 answer
asked by
Amy~
528 views
3-cos1-1=
1 answer
68 views
what is the limit n to infinite of
cos1*cos(1/2)*cos(1/4)*cos(1/8)*cos(1/16)*...*cos(1/2^n)
1 answer
asked by
CHRIS
590 views
If A is between 270degrees and 360degrees, and cos A=12/13, find the exact value of:
sin2a, cos2a, sin1/2a, cos1/2a
2 answers
asked by
Bob
1,191 views
Verify the identity.
sin2x/cosx + sinx = 2sinx Solve for all values of x: 6cos2x-7cosx-3=0 If f(x)=cos1/2x-sin2x find the value
1 answer
asked by
.
903 views
cosA= 5/9 find cos1/2A
are you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
0 answers
asked by
Anonymous
842 views