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How much 6M HNO3 will

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  1. How many mL of a 0.5M Ca(OH)2 solution are needed to neutralize 38 mL of a 2M HNO3 solution?ANSWER IS: x = multiply / = divide
    1. answers icon 1 answer
    2. ChemistryAngel asked by ChemistryAngel
    3. views icon 777 views
  2. Calculate the concentration of an aqueous HNO3 solution that has a pH=5.08.pH = 5.08. Convert that to (H^+). Since HNO3 is a
    1. answers icon 0 answers
    2. Taasha asked by Taasha
    3. views icon 768 views
  3. I have a few question for my review.1) How would you prepare 30.0 ml of 0.600M HNO3 From a stock solution of 4.00M HNO3? What
    1. answers icon 4 answers
    2. Matt asked by Matt
    3. views icon 519 views
  4. 245 Mol/dm³ of HNO3 neutralizes 0.450 mol/dm² of 25 cm³ Na₂CO3.Calculate the Concentration of HNO3 in (a) mol/dm³ (b)
    1. answers icon 1 answer
    2. Fatorma asked by Fatorma
    3. views icon 146 views
  5. A 15.7mL sample of HNO3 reacts to neutralize 27.7mL of 0.187M KOH solution. What is the molarity of the HNO3 solution?HNO3 + KOH
    1. answers icon 0 answers
    2. Kellie asked by Kellie
    3. views icon 1,150 views
  6. How many mL of 3.00M HNO3 would you need to make exactly 100mL of 0.83 HNO3 by dilution with water? (The FM of HNO3 = 63.0.)
    1. answers icon 2 answers
    2. Lauren asked by Lauren
    3. views icon 973 views
  7. How would you make up 255 mL of 0.150 M HNO3 from nitric acid that is 68.0% HNO3?The density of 68.0% HNO3 is 1.41 g/mL.
    1. answers icon 3 answers
    2. Henry asked by Henry
    3. views icon 520 views
  8. Calculate the pH of the solution after the addition of the following amounts of 0.0617 M HNO3 to a 70.0 mL solution of 0.0750 M
    1. answers icon 1 answer
    2. Owen asked by Owen
    3. views icon 1,366 views
  9. A volume of 29.62 ± 0.05 mL of HNO3 solution was required for complete reaction with 0.8896 ± 0.0008 g of Na2CO3, (FM 105.988
    1. answers icon 0 answers
    2. Amanda asked by Amanda
    3. views icon 686 views
  10. A volume of 29.62 ± 0.05 mL of HNO3 solution was required for complete reaction with 0.8896 ± 0.0008 g of Na2CO3, (FM 105.988
    1. answers icon 0 answers
    2. Amanda asked by Amanda
    3. views icon 659 views