How many grams of N2F4

14.0g of F2 was reacted with excess NH3 to produce N2F4 and HF. The equation for the reaction: 5F2(g) + 2NH3(g) - N2F4(g) +
1. 1 answer
2. 133 views
5F2(g) + 2NH3(g) ==> N2F4(g) + 6HF(g)a)If you have 66.6 g NH3, how many grams of F2 are required for complete reaction? b)How
1. 2 answers
2. asked by Danny
3. 3,685 views
what do limiting reagents have to do with...5F2(g) + 2NH3(g) ==> N2F4(g) + 6HF(g) a)If you have 66.6 g NH3, how many grams of F2
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2. asked by Keith
3. 1,813 views
5F2(g) + 2NH3(g) ==> N2F4(g) + 6HF(g) If you have 225 g F2, how many grams of N2F4 will be produced
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2. asked by Kyra
3. 564 views
Based on the balanced equation,10Li + N2F4 → 4LiF + 2Li3N calculate the formula units of LiF formed when 54 molecules of N2F4
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2. asked by eng
3. 678 views
How many grams of N2F4 can be produced from 361 g F2?
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2. asked by Marlon
3. 1,031 views
if 68.0g of NH3 react with 304g of F2, how many grams of N2F4 are produced
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2. asked by annaleisa
3. 581 views
Need help with my last question!Given the following reaction: 2NH3 (g) + 5F2 (g) ---> N2F4 (g) + 6HF (g) If 4.00 g of NH3 and
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2. asked by kaitie
3. 1,000 views
The reaction of flourine with ammonia produces dinitrogen tetrafluoride and hydrogen fluoride.5F2(g) + 2NH3(g) ==> N2F4(g) +
1. 3 answers
2. asked by Keith
3. 2,242 views
The reaction of fluorine with ammonia produces dinitrogen tetra fluoride and hydrogen fluorida.5F2(g)+2NH(g)---> N2F4(g)+6HF(g)
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2. asked by Lexa
3. 1,158 views