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How many grams of N2F4
14.0g of F2 was reacted with excess NH3 to produce N2F4 and HF. The equation for the reaction: 5F2(g) + 2NH3(g) - N2F4(g) +
1 answer
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5F2(g) + 2NH3(g) ==> N2F4(g) + 6HF(g)
a)If you have 66.6 g NH3, how many grams of F2 are required for complete reaction? b)How
2 answers
asked by
Danny
3,557 views
what do limiting reagents have to do with...
5F2(g) + 2NH3(g) ==> N2F4(g) + 6HF(g) a)If you have 66.6 g NH3, how many grams of F2
1 answer
asked by
Keith
1,757 views
5F2(g) + 2NH3(g) ==> N2F4(g) + 6HF(g) If you have 225 g F2, how many grams of N2F4 will be produced
2 answers
asked by
Kyra
516 views
Based on the balanced equation,
10Li + N2F4 → 4LiF + 2Li3N calculate the formula units of LiF formed when 54 molecules of N2F4
1 answer
asked by
eng
640 views
How many grams of N2F4 can be produced from 361 g F2?
1 answer
asked by
Marlon
996 views
if 68.0g of NH3 react with 304g of F2, how many grams of N2F4 are produced
1 answer
asked by
annaleisa
550 views
Need help with my last question!
Given the following reaction: 2NH3 (g) + 5F2 (g) ---> N2F4 (g) + 6HF (g) If 4.00 g of NH3 and
1 answer
asked by
kaitie
950 views
The reaction of flourine with ammonia produces dinitrogen tetrafluoride and hydrogen fluoride.
5F2(g) + 2NH3(g) ==> N2F4(g) +
3 answers
asked by
Keith
2,182 views
The reaction of fluorine with ammonia produces dinitrogen tetra fluoride and hydrogen fluorida.
5F2(g)+2NH(g)---> N2F4(g)+6HF(g)
1 answer
asked by
Lexa
1,101 views