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Hello. I am trying to simplify the problem, (tan^2x-sec^2x)/cosx, but
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
asked by
Anonymous
1,054 views
Hello.
I am trying to simplify the problem, (tan^2x-sec^2x)/cosx, but I am unsure how. Does anyone have any formulas or starting
2 answers
asked by
Taylor
133 views
Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1 answer
asked by
Anonymous
1,321 views
Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
4 answers
asked by
Anonymous
1,928 views
Use the fundamental identities to simplify the expression.
csc Q / sec Q so this would be 1/sinx / 1/cosx and then 1/sinx times
1 answer
asked by
Hannah
559 views
Use the fundamental identities to simplify the expression.
csc Q / sec Q so this would be 1/sinx / 1/cosx and then 1/sinx times
1 answer
asked by
Hannah
615 views
Use the fundamental identities to simplify the expression.
csc Q / sec Q so this would be 1/sinx / 1/cosx and then 1/sinx times
1 answer
asked by
Hannah
574 views
How do you simplify:
(1/(sin^2x-cos^2x))-(2/cosx-sinx)? I tried factoring and creating a LCD of (sinx+cosx)(sinx cosx)
2 answers
asked by
Shannon
569 views
Integrate sinx(cosx)^2dx using the substitution u=sinx. I know how to do this using u =cosx, but not sinx. The next problem on
2 answers
asked by
Larry
777 views
Simplify: (1/secx+sin^2x/cosx)cosx.
Explain alittle bit, not just do the steps please.
1 answer
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does it matter at this point?
448 views