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Given the equation 2C8H18 +
Calculate the standard enthalpy change for the reaction:
2C8H18(l) + 17O2(g) --> 16CO(g) + 18H2O(l) Given: 2C8H18(l) + 25O2(g)
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asked by
Anon
2,140 views
Calculate the standard enthalpy change for the reaction 2C8H18(l)+17O2(g)> 16CO(g) + 18H2O(l)
Given
2 answers
asked by
Nicole
4,233 views
Is the following a properly written thermochemical equation?
2C8H18 + 25O2 → 16CO2 + 18H2O, ΔH = –5,471 kJ/mol No, the
1 answer
asked by
AM
2,028 views
Which equation is a correctly written thermochemical equation?
Question 8 options: NH4Cl --> NH4+ + Cl- 2C8H18 + 25O2 --> 16CO2 +
1 answer
58 views
Given the equation 2C8H18 + 25O2 = 16 CO2 + 18H2O: How many moles of oxygen gas (O2) are consumed upon combustion of 2.20 L of
2 answers
asked by
Chris
1,854 views
This balance equation shows the burning of octane in air. 2C8H18 + 25O2 ----> 16CO2 + 18H2O. How many grams of carbondioxide
1 answer
asked by
Shane
856 views
255 grams of octane and 1510 grams of oxygen gas are present at the beginning of reaction
that goes to completion and forms
1 answer
asked by
Tekalign
209 views
255 grams of octane and 1510 grams of oxygen gas are present at the beginning of reaction that goes to completion and forms
1 answer
asked by
Keby
248 views
Given the equation 2C8H18 + 25O2 = 16 CO2 + 18H2O: The combustion of octane produces carbon dioxide and water. If you start with
1 answer
asked by
Brittany
883 views
0. A common gasoline additive is octane, C8H18. When octane is burned it produces heat
according to the following equation.
1 answer
275 views