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Given that \displaystyle \int_0^4 x^3\sqrt{9+x^2}
Given that \displaystyle \int_0^4 x^3\sqrt{9+x^2} dx = a, what is the value of \lfloor a \rfloor?
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John
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Given that \displaystyle \int_0^4 x^3\sqrt{9+x^2} dx = a, what is the value of \lfloor a \rfloor?
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asked by
John
1,008 views
Consider the general case where the two classes have different means and possibly different variances:
\displaystyle
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Given two data points in 2 dimensions:
\displaystyle \displaystyle \mathbf{x}^{(1)} \displaystyle = \displaystyle (x^{(1)},
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Given two data points in 2 dimensions:
\displaystyle \displaystyle \mathbf{x}^{(1)} \displaystyle = \displaystyle (x^{(1)},
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The normal distribution \mathcal{N}(\theta ,1) with with mean \theta and known variance \sigma ^2=1 has pdf
\displaystyle
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Given \displaystyle \int_0^{\frac{3\pi}{2}} x^2\cos x \, dx = a - \frac{b\pi^2}{c}, where a, b and c are positive integers and b
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John
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Consider the same statistical set-up as above. Suppose we observe a data set consisting of 1000 observations as described in the
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Recall from the slides that the Gamma distribution can be reparameterized using the two parameters a, the shape parameter, and
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For the two following pmfs with one parameter \theta that are written in the form
\displaystyle \displaystyle f_\theta (y)
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