Search: Given p(x)=x^4 ax^3 bx^2 cx d,such that x=0 is the only real root of p'(x)=0.If p(-1)

The only real root of x^3 - 1999x^2+x-1999=0 is 1999. What is the only real root of (x-1)^3-1999(x-1... why is this answer no real root? -5x^6=320? Approximate the real root of cosx+x=2 to four decimal place. (Using Newton's method) I need help... When a root is not a real number, what kind of number is it? Find the real-number root. square root negative one point twenty-one Find the real-number root. sq root of -1.21 (1 point) -0.605 1.1 -1.1 no real numb... Find the real-number root. −3.82−−−−−√ (1 point) Responses 1.95 1.95 -1.95 -1.95 Infinite Real Numbe... Find the real root of the equation 3x-cosx-1=0 correct to four decimal places using the Newton Raph... find real solutions sq.root 2x+5 - sq.root x+6 = 1 Find the real-number root.%0D%0A−3.82−−−−−√%0D%0A−%0D%0A3.82%0D%0A (1 point)%0D%0AResponses%0D%0A%0D...