Given f(x)=sin(x)-2cos(x) on the interval

Find all solutions on the interval [0.2pi)A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8cos^2(t)=3-2cos(t) All i did was move
1. 1 answer
2. asked by Dan
3. 841 views
Given that 2cos^2 x - 3sin x -3 = 0, show that 2sin^2 x + 3sin x +1 = 0?Hence solve 2cos^2 x + 4sin x - 3 = 0, giving all
1. 2 answers
2. asked by Sean
3. 982 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 866 views
Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2cos^(2)\theta +\sqrt(2cos\theta
1. 1 answer
2. asked by Yana
3. 628 views
Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
1. 1 answer
2. asked by Maria
3. 1,643 views
cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
1. 0 answers
2. asked by Anonymous
3. 815 views
Given f(x)=sin(x)-2cos(x) on the interval [0,2pi]. Determine where the function is concave up and concave down, and increasing
1. 0 answers
2. asked by Shane
3. 563 views
Solve the equation on the interval [ 0, 2 pi] (tan x + ?3)(2cos x + 1) = 0
1. 4 answers
2. asked by Kelly
3. 902 views
Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0
1. 1 answer
2. asked by Sierra
3. 1,316 views
Find all solutions on the interval (0,2pi):2-2cos^2=sinx+1
1. 2 answers
2. asked by Help needed!
3. 626 views