Given f(x)=sin(x)-2cos(x) on the interval

  1. Find all solutions on the interval [0.2pi)A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8cos^2(t)=3-2cos(t) All i did was move
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    2. Dan asked by Dan
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  2. Given that 2cos^2 x - 3sin x -3 = 0, show that 2sin^2 x + 3sin x +1 = 0?Hence solve 2cos^2 x + 4sin x - 3 = 0, giving all
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    2. Sean asked by Sean
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  3. the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
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    2. alex asked by alex
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  4. Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2cos^(2)\theta +\sqrt(2cos\theta
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    2. Yana asked by Yana
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  5. Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
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    2. Maria asked by Maria
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  6. cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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    2. Anonymous asked by Anonymous
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  7. Given f(x)=sin(x)-2cos(x) on the interval [0,2pi]. Determine where the function is concave up and concave down, and increasing
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    2. Shane asked by Shane
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  8. Solve the equation on the interval [ 0, 2 pi] (tan x + ?3)(2cos x + 1) = 0
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    2. Kelly asked by Kelly
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  9. Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0
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    2. Sierra asked by Sierra
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  10. Find all solutions on the interval (0,2pi):2-2cos^2=sinx+1
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    2. Help needed! asked by Help needed!
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