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Given f(x)=sin(x)-2cos(x) on the interval
Find all solutions on the interval [0.2pi)
A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8cos^2(t)=3-2cos(t) All i did was move
1 answer
asked by
Dan
841 views
Given that 2cos^2 x - 3sin x -3 = 0, show that 2sin^2 x + 3sin x +1 = 0?
Hence solve 2cos^2 x + 4sin x - 3 = 0, giving all
2 answers
asked by
Sean
982 views
the problem is
2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
3 answers
asked by
alex
866 views
Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2cos^(2)\theta +\sqrt(2cos\theta
1 answer
asked by
Yana
628 views
Find all solutions to the equation in the interval [0, 2pi)
cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
1 answer
asked by
Maria
1,643 views
cosA= 5/9 find cos1/2A
are you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
0 answers
asked by
Anonymous
815 views
Given f(x)=sin(x)-2cos(x) on the interval [0,2pi]. Determine where the function is concave up and concave down, and increasing
0 answers
asked by
Shane
563 views
Solve the equation on the interval [ 0, 2 pi] (tan x + ?3)(2cos x + 1) = 0
4 answers
asked by
Kelly
902 views
Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0
1 answer
asked by
Sierra
1,316 views
Find all solutions on the interval (0,2pi):
2-2cos^2=sinx+1
2 answers
asked by
Help needed!
626 views