Given f(x)=1+2cos x , find

  1. cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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    2. Anonymous asked by Anonymous
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  2. What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
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    2. Anonymous asked by Anonymous
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  3. Find all solutions on the interval [0.2pi)A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8cos^2(t)=3-2cos(t) All i did was move
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    2. Dan asked by Dan
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  4. how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
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  5. Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
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    2. Miley asked by Miley
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  6. Find minimum value of 2cos x + 2cos y
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    2. vikrant asked by vikrant
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  7. Find minimum value of 2cos x + 2cos y
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    2. vikrant asked by vikrant
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  8. Find minimum value of 2cos x + 2cos y
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    2. vikrant asked by vikrant
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  9. If √2cos(x)-1 = (1+√3)/2 and √2cos(x)+1 = (1-√3)/2, find the value of cos4x.
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    2. sh asked by sh
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  10. Identify the equation for the following graph: (1 point) Responses y=2cos(2x) y is equal to 2 cosine 2 x y=−2cos(2x) y is
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