Given \displaystyle \int_0^{\frac{3\pi}{2}} x^2\cos x

Given \displaystyle \int_0^{\frac{3\pi}{2}} x^2\cos x \, dx = a - \frac{b\pi^2}{c}, where a, b and c are positive integers and b
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The normal distribution \mathcal{N}(\theta ,1) with with mean \theta and known variance \sigma ^2=1 has pdf\displaystyle
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Recall from the slides that the Gamma distribution can be reparameterized using the two parameters a, the shape parameter, and
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Consider the general case where the two classes have different means and possibly different variances:\displaystyle
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Given that \displaystyle \int_0^4 x^3\sqrt{9+x^2} dx = a, what is the value of \lfloor a \rfloor?
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Given that \displaystyle \int_0^4 x^3\sqrt{9+x^2} dx = a, what is the value of \lfloor a \rfloor?
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Given two data points in 2 dimensions:\displaystyle \displaystyle \mathbf{x}^{(1)} \displaystyle = \displaystyle (x^{(1)},
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Given two data points in 2 dimensions:\displaystyle \displaystyle \mathbf{x}^{(1)} \displaystyle = \displaystyle (x^{(1)},
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In this exercise we want to understand a little better the formula\frac{1}{\displaystyle {\sum _{i=0}^{n} \frac{1}{\sigma _
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a and b are integers that satisfy: \displaystyle \lim_{x \to 1} \frac{x-1}{x^2-ax+b} = -\frac{1}{3}. What is the value of a+b?
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