For z1 = 4cis(7pi/6)and z2

Multiply.6√6cis(5π/9)⋅3√4cis(3π/4)
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For z1 = 4cis(7pi/6)and z2 = 3ci(pi/3), find z1 · z2 in rectangular form.A.12 − 12i B.-12 − 12i C.12 + 12i D.12i E.-12i
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2. asked by Chris
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For z1 = 4cis (7pi/6) and z2 = 3cis(pi/3), find z1 * z2 in rectangular form.
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2. asked by Anonymous
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For z1 = 4cis (7pi/6) and z2 = 3cis(pi/3), find z1 * z2 in rectangular form.
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2. asked by Sam
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17) Convert the rectangular form of the complex number into polar form.z= 2-2√3i A: z=4(cos 2pi/3 + i sin 2pi/3) B: z = 4cis
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2. asked by cal
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Multiply. √3/2cis(2π/9)·√6/4cis(3π/2). Which is the answer?A)2√3/8cis(31π/18) B)3√2/8cis(π/3) C)3√2/8cis(31π/18)
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2. asked by cass.
3. 1,337 views