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For the curve y=2^[sqrt(9-x2)], find
Find the area of the surface of revolution generated by revolving the curve y = 3 sqrt (x), 0 <= x <= 4, about the x-axis.
Okay,
1 answer
asked by
Anon
2,276 views
The curve y = |x|/(sqrt(5- x^2)) is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point
2 answers
asked by
TayB
6,109 views
The curve y =|x|/(sqrt(5−x^2))
is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point
1 answer
asked by
TayB
874 views
Given the curve defined by the equation y=cos^2(x) + sqrt(2)* sin(x) with domain (0,pi) , find all points on the curve where the
1 answer
asked by
Ashok
701 views
Find the point on the curve y=x^2 closest to point (0,1)
Here's what I have: Sqrt {(x-0)^2 + ((x^2)-1)} Sqrt {((x^2) + (x^2)-1}
4 answers
asked by
Mandy
1,139 views
1)Find the exact value of cos 105 by using a half-angle formula.
A)sqrt 2 - sqrt 3 /2 B)-sqrt 2 - sqrt 3 /2 C)-sqrt 2 + sqrt 3 /2
7 answers
asked by
Jon
3,568 views
Use implicit differentiation to find the slope of the tangent line to the curve sqrt of x + sqrt of y = 8
1 answer
asked by
gnozahs
1,377 views
find the slope of the tangent line to the curve (sqrt 2x+4y) + (sqrt 4xy) = 9.16
at the point (1,5) dy/dx method implicit
1 answer
asked by
sal
835 views
Find the arc length of the given function/curve on the given interval.
y=ln(x-sqrt(x^(2)-1)); x ϵ [1, sqrt(2)]
1 answer
asked by
kales
1,066 views
Find the arc length of the given function/curve on the given interval.
y=ln(x-sqrt(x^(2)-1)); x ϵ [1, sqrt(2)]
0 answers
asked by
kales
528 views