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For more than 4000 years
Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x
𝑓 ( 𝑥 ) = 4000 ( 1.06 ) 𝑥
1 answer
asked by
ionk
52 views
If 50% of a radioactive element remains after 4000 years, what is the half-life?
a 2000 years b 4000 years c 8000 years d 12000
1 answer
38 views
Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x) = 4000(1.06)^x is the number of years since
1 answer
29 views
Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x
, where x is the number of years
1 answer
44 views
5.
Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x , where x is the number of years
1 answer
46 views
Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x
, where x is the number of years
1 answer
23 views
Pizzazz Publications is having some books printed. The printer charges $800 plus $5 per book. What equation could help me find
1 answer
16 views
Approximately how long have people depended on the Nile River?
Question 8 options: For about 1000 years For about 2000 years For
1 answer
asked by
Nathan Fry
91 views
Which length of time is accurately represented?
The years 1920 to 1929 are an era. The years 3001 to 4000 are a decade. The years
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asked by
humaira likes ukasha guys
18 views
Six years after buying 100 shares of xyz stock for $40 per share you sell the stock for 6400.
6400-4000/4000=0.6 6400/4000=1.6 yx
1 answer
asked by
Anonymous
1,131 views