Find the value of tan2x,

find all solutions in interval [0,2pi]tan²x = -3/2 secx This question may look tricky, but its actually quite simple. First:
1. 0 answers
2. asked by ethan
3. 727 views
solve: tanx+tan2x+√3tanx tan2x=√3 (0<=x<=360)
1. 3 answers
2. asked by rabin
3. 4,828 views
Solve the equation on the interval [0, 2π).tan2x sin x = tan2x would it be 0, pi/2 ?
1. 1 answer
2. asked by Liz
3. 1,533 views
Prove that cosec²x(tan²x-sin²x)=tan²x
1. 1 answer
2. 145 views
secx = 4 in Q2 find sin2x,cos2x,tan2x
1. 2 answers
2. asked by j
3. 852 views
tanx= -12/5 x in Q 2.find sin2x= cos2x= tan2x=
1. 1 answer
2. asked by Sam
3. 685 views
Find the value of tan2x, (pi/2)<x<pi, given secx=-5/4.So cosx=-4/5? I've no clue what to do next.
1. 2 answers
2. asked by sh
3. 645 views
Find the equation of the line tangent to y=tan2x at x=pi/8A. y-1=sqrt(2)(x-pi/8) B. y-1=1/2(x-pi/8) C. y-1=1/4(x-pi/8) D.
1. 1 answer
2. asked by Sarah
3. 2,406 views
tanx= -12/5 x in quadrant 2find; sin2x= cos2x= tan2x=
1. 1 answer
2. asked by Adam
3. 1,555 views
If sinx=-1/2 and x terminates in the third quadrant, find the exact value of tan2x.
1. 2 answers
2. asked by Brenda
3. 843 views