Search: Find the point where the tangent to the curve is horizontal. f(x) = (x^2-2x 4)/(x^2 4)

find the tangent to the curve given by the parametric equations: x=1/t y=sqrt(t)e^(-t) find the tangent to the curve y=e^(x^2+3x)+2x at the point x=1 Find the curve's unit tangent vector. Also, find the length of the indicated portion of the curve.... Find the point(s) on the curve y=x^2 that is/are closest to the point (0,3). If you use your calcula... Find the point on the curve y =2/3 〖√(18-x^2 )〗 (first quadrant) where a tangent line may be drawn... Find the point on the curve y = 1/x^2 ,( x > 0 ), where the curvature is maximum. Find a point P on curve y = x^3 such that the slope of the line passing through point P & (1,1) is 3... Find the point on the curve y=1 x2+14 x such that the tangent line to the curve is parallel to 2 x +... Find the point on the curve y = x^3 which is nearest the point (4, 0). Find the point on the curve y=3-x^2 that is closest the point A(6,0).