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Find the area of the region in the first quadrant
The equations y=-2X+12, y=6-X, and X=0 enclose a region in quadrant I. when that region is reflected over the line y=6-X, a
0 answers
asked by
Josh
527 views
The region R is the region in the first quadrant bounded by the curves y = x^2-4x+4, x=0, and x=2.
Find a value h such that the
4 answers
asked by
Anonymous
1,634 views
Let R be the region in the first quadrant under the graph of y=1/sqrt(x) for 4</=x</=9.
(a)Find the area of R. I took the
3 answers
asked by
Anonymous
5,013 views
Sketch the region in the first quadrant enclosed by y=6/x, y=2x, and y=.5x. Decide whether to integrate with respect to x or y.
3 answers
asked by
Nick
732 views
1. Let R be the region in the first quadrant enclosed by the graphs of y=4-X , y=3x , and the y-axis.
a. Find the area of region
1 answer
asked by
Taeyeon
3,272 views
Find the area of the region IN THE FIRST QUADRANT (upper right quadrant) bounded by the curves y=sin(x)cos(x)^2, y=2xcos(x^2)
1 answer
asked by
Mishaka
2,628 views
The following are about an infinite region in the 1st quadrant between y=e^-x and the x-axis.
A) Find the area of the region
2 answers
asked by
Tim
2,869 views
Find the area of the region IN THE FIRST QUADRANT (upper right quadrant) bounded by the curves y=sin(x)cos(x)^2, y=2xcos(x^2)
3 answers
asked by
Mishaka
1,968 views
A region is bounded in the second quadrant by the curve y = ln(1–x), the line y=3, and the y-axis. Find the area of the
2 answers
asked by
bex
1,061 views
Sketch the region in the first quadrant enclosed by y=6/x, y=2x, and y=12x. Decide whether to integrate with respect to x or y.
3 answers
asked by
Nick
3,965 views