Find limit of 2x+1-cosx/3x as

Find the derivative of the function.y = integral from cosx to sinx (ln(8+3v)) dv lower limit = cosx upper limit = sinx y'(x) =
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2. asked by Tim
3. 1,552 views
My question is:Use L'Hospital's rule to find limit as x approaches 0 (e^x-e^-x-2x)/x-sinx. 1st I took the derivative to get
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2. asked by Jessica
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Find limit of 2x+1-cosx/3x as x approaches 0?
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2. asked by sential
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Find the limit of cosx/(1-sinx) as x->(pi/2) from + side
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2. asked by Patricia
3. 480 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
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2. asked by Anonymous
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Using L'Hopital's rule find the limit if exists of;lim x->1 (cosx)/(pi-2x) I got (sinx)/2 but i am not sure about this> Can
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2. asked by Nikita
3. 544 views
hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
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2. asked by elle
3. 715 views
Calculus Limit Problem:Evaluate the function at the given numbers (correct to six decimal places). Use the results to guess the
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2. asked by George
3. 650 views
I have a question relating to limits that I solvedlim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by
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2. asked by Alex
3. 691 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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2. asked by Dave
3. 1,446 views