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Find dydx if y=log9(x2−1) .
Find dydx if y=log9(x2−1) .
1 answer
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Find dy/dx if y=csc(2x−−√) . (1 point) Responses dydx=−csc(2x√)cot(2x√)x√ d y d x = − csc ( 2 x ) cot ( 2 x ) x
1 answer
109 views
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
1 answer
asked by
Joe
726 views
Find dydx if y=csc3x+1−−−−−√ . (1 point) Responses dydx=−3csc3x+1√ ⋅ cot3x+1√3x+1√ d y d x = − 3 csc 3 x
1 answer
59 views
Find dy/dx if y=sinx⋅sin−1x . (1 point) Responses dydx=cosx ⋅ sin−1x+sinx1+x2 d y d x = cos x · sin − 1 x + sin x 1 +
1 answer
85 views
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
4 answers
asked by
Joe
642 views
Algebraically determine the value(s) of x: log9(x-5)=1-log9(x+3)
Please help me. Thanks!
1 answer
asked by
Hannah
380 views
Find dydx for y=sin−1(1x√) .
1 answer
29 views
Find dydx for y=sin^−1(1√x) .
1 answer
30 views
Find dydx if y=3x⋅5x .
1 answer
36 views