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Find an equation of a circle that satisfies the given

find an equation of a circle that satisfies the given conditions through 3,4 slope 0
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2. asked by Shy
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Find an equation of a circle that satisfies the given conditions.Center (–2, –8), radius 10
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2. asked by wikki4way
3. 82 views
Find the equation of the circle that satisfies the given conditions.Center at the origin and passes through (7, 9) 130 = ?
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2. asked by Dee
3. 1,791 views
1) Circle centre (7,-2) passes through (-2,10). Calculate radius and find equation of circle.2) AB is diameter of circle A(9,5)
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2. asked by Anonymous
3. 724 views
The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original
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2. asked by Jossie
3. 1,117 views
The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original
1. 0 answers
2. asked by Jossie
3. 1,176 views
The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original
1. 2 answers
2. asked by Jossie
3. 917 views
The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original
1. 0 answers
2. asked by Jossie
3. 706 views
write the equation of the circle that satisfies each set of conditions.the center of the circle is on the x-axis, its radius is
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2. asked by Mk
3. 745 views
Hi guys,In the question "It is given that P (0, 3), Q(7, 5), R(9, -2) and S are vertices of a square. A circle A passes through
1. 5 answers
2. asked by Joshua
3. 657 views